Question

Write the equation of the line that it is perpendicular to 5x+8y=16 and passes through (-5,7)

Answer 1

5x + 8y=16 -> y = -5 / 8 x +16 / 8 (2) = -5 / 8 x + 2 use the slope to find the y intercept. Line is parallel so use m= -5 / 8 (-5 , 7) -> 7 = (-5 / 8 ) (-5) + b 7 = 25 / 8 + b -> 8 ( 7 = 25 / 8 + b) 56= 25 + 8b 56-25 = 8b b= 31 / 8 so , y = -5 / 8 x + 31 /8.