Question

You roll a six-sided die two times what is the probability of rolling a two and then rolling a 1

Answer 1

Answer:
`Pr(rolling\text{ a 2 and 1\rparen= }(1)/(36)`

Step-by-step explanation:

Given:

A six-sided die rolled twice

To find:

the probability of rolling a two and then a 1

To determine the probability, we need to find the probability of rolling a 2 and the probability of rolling a 1

Pr(rolling 2) = number of times 2 occurs/total

in a six-sided die, total = 6; and 2 occur once

`Pr(rolling\text{ a 2\rparen = }(1)/(6)`

Pr(rolling 1) = umber of times 1 occurs/total

1 occur once

`Pr(rolling\text{ 1\rparen = }(1)/(6)`

Pr(rolling a 2 and then 1) = Pr(rolling 2) × Pr(rolling 1)

`\begin{gathered} Pr(rolling\text{ a 2 and 1\rparen = }(1)/(6)\text{ }*\text{ }(1)/(6) \\ \\ Pr(rolling\text{ a 2 and 1\rparen = 1/36} \end{gathered}`