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light incident on a polarizer is then passed through a second polarizer. if the polarizer and the analyzer are perpendicular to each other, what can you say about the light waves emerging from the second polarizer?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????

User Mark Smith
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2 Answers

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Indeed, this is one of the odd results in physics. A system of two polarizing filters arranged as shown below trasmits no light.
User Marmstrong
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Answer:

The intensity of light emerging from the second polarizer is zero.

Step-by-step explanation:

The angle between the axis of first polarizer and the second polarizer is 90°.

According to the law of Malus


I = I_(0)* Cos^(2)\Theta

where,
I_(0) be the intensity of incident light on first polarizer and I be the intensity of light emerging out from second polarizer.

The intensity of light emerging out from first polarizer is given by


I_(1)=(I_(0))/(2)

the inetnsity of light emerging out from second polarizer is given by


I = I_(1)* Cos^(2)90


I = 0

Thus, no light waves are emerging out from the second polarizer.

User NenTi
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