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the following scores in their end-of-year math What was the mean deviation of their scores? 23%, 37%, 45%, 49%, 56%, 63%, 63%, 70%, 72%, and 82% A. 14% B. 15% C. 16% D. 17%

User Zrslv
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1 Answer

15 votes
15 votes

First, we need to compute the mean for these 10 values:


\mu=(23+37+45+49+56+63+63+70+72+82)/(10)

hence,


\begin{gathered} \mu=(560)/(10) \\ \mu=56 \end{gathered}

Now, we need to find the distance of each value from that mean


\begin{gathered} \text{Value Distance form 56 } \\ 23\text{ }33 \\ 37\text{ }19 \\ 45\text{ 11} \\ 49\text{ 7} \\ 63\text{ 7} \\ 63\text{ 7} \\ 70\text{ 4} \\ 72\text{ 6} \\ 82\text{ }26 \end{gathered}

Finally, we must find the mean of those distances:


\begin{gathered} \operatorname{mean}\text{ deviation=}(33+19+11+3+7+7+4+6+26)/(10) \\ \operatorname{mean}\text{ deviation=}(116)/(10) \\ \operatorname{mean}\text{ deviation=}11.6 \end{gathered}

User Monish Khatri
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