Let x represent the price of each adult ticket.
Let y represent the price of each student ticket
On the first day of the ticket sales, the school sold 6 adult tickets and 2 student tickets or a total of $96. This means that they sold 6 * x adult tickets and 2 * y student tickets. The equation would be
6x + 2y = 96
The school took in $232 on the second day by selling 2 adult tickets and 14 student
tickets. This means that they sold 2 * x adult tickets and 14 * y student tickets. The equation would be
2x + 14y = 232
We would solve both equations by using the method of elimination. To eliminate x, we would multiply the first equation by 1 and the second equation by 3. This would make the coefficient of x to be equal in both equations.
Multiplying the first equation by 1, it becomes
6x + 2y = 96 equation 3
Multiplying the second equation by 3, it becomes
6x + 42y = 696 equation 4
We would subtract equation 4 from equation 3. It becomes
6x - 6x + 2y - 42y = 96 - 696
- 40y = - 600
y = - 600/- 40
y = 15
We would substitute y = 15 into the first equation. It becomes
6x + 2 * 15 = 96
6x + 30 = 96
6x = 96 - 30 = 66
x = 66/6
x = 11
Each adult ticket cost $11
Each student ticket cost $15