The length of a rectangle is five less than twice it's width.if the perimeter of the rectangle is 56 inches,find its dimensions.

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asked Nov 24, 2018 55.7k views

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Nitin Karande · Answer 1 · 2018-11-29T08:23:12+0000

P = 2(L + W)
P = 56
L = 2W - 5

56 = 2(2W - 5 + W)
56 = 2(3W - 5)
56 = 6W - 10
56 + 10 = 6W
66 = 6W
66/6 = W
11 = W <=== width is 11 inches

L = 2W - 5
L = 2(11) - 5
L = 22 - 5
L = 17 <=== length is 17 inches

The length of a rectangle is five less than twice it's width.if the perimeter of the rectangle is 56 inches,find its dimensions.

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