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What is the equation for the problem In 2003, the price of a certain automobile was approximately $33,700 with a depreciation of $2,150 per year. After how many years will the c…
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What is the equation for the problem In 2003, the price of a certain automobile was approximately $33,700 with a depreciation of $2,150 per year. After how many years will the c…
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Aug 28, 2018
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what is the equation for the problem In 2003, the price of a certain automobile was approximately $33,700 with a depreciation of $2,150 per year. After how many years will the car's value be $18,650?
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The equation is
18650=33700-2150x
Where x is the number of years
Solve the equation for x to find how many years will the car's value be $18,650
First move terms
2150x=33700-18650
Subtract the numbers
2150x=15050
Divide both sides by 2150
X=15050/2150
X=7 years
Hope it helps!
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Sep 4, 2018
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