Question

Determine the displacement of a plane that is uniformly accelerated from 66 m/s to 88 m/s in 12 s

Explain

Answer 1

The displacement of the plane that is uniformly accelerated from 66 m/s to 88 m/s in 12 s is 264 meters.

Step-by-step explanation:

To determine the displacement of a plane that is uniformly accelerated, we can use the formula:

Displacement (d) = (Final velocity (v) - Initial velocity (u)) * Time (t)

Given that the initial velocity (u) is 66 m/s, the final velocity (v) is 88 m/s, and the time (t) is 12 seconds, we can substitute these values into the formula:

d = (88 - 66) * 12 = 264 meters

So, the displacement of the plane is 264 meters.

Answer 2

Displacement is the area under the graph for velocity-time graph so if plane accelerated uniformly from 66m/s to 88m/s the area will be the area of trapezium where formula for area under trapezium is 1/2 (sum of parallel lines) x height so the parallel lines in this case are 66m/s and 88m/s and height is time taken which is 12 so displacement is 1/2 (66+88)(12)= 924m

if you want to know the formula then it is S=1/2 (V+U)(t) where S is displacement V is final velocity U is initial velocity and t is time taken