Question

If 32.73g of FePO4 react with excess Na2SO4 how many grams of Fe2 (SO4)3 can be made?

Answer 1

First, we must write our reaction and balance it:

2 FePO4 + 3 Na2SO4 => Fe2(SO4)3 +2 Na3PO4 (balanced)

We have 32.73 g FePO4 that reacts, and we want to get the amount of Fe2(SO4)3 produced.

The excess here is Na2SO4

We also need the molar masses for FePO4 (150.8 g/mol) and for Fe2(SO4)3 (399.8 g/mol)

Procedure:

2 x 150.8 g FePO4 ------------------- 399.8 g Fe2(SO4)3

32.73 g FePO4 ------------------- X

X = 32.73 g x 399.8 g/ 2 x 150.8 g = 43.39 g

Answer: 43.39 g of Fe2(SO4)3