171,030 views
37 votes
37 votes
Find the sample variance and standard deviation.22, 15, 3, 9, 8Choose the correct answer below. Fill in the answer box to complete your choice.(Type an integer or a decimal. Round to one decimal place as needed.)O A. S2=B. o

User Bronya
by
3.1k points

1 Answer

12 votes
12 votes

Answer

A) Variance = σ² = 212.1

B) Standard Deviation = σ = 14.6

Step-by-step explanation

The standard deviation is the square root of variance. And variance is an average of the squared deviations from the mean.

Mathematically for a sample distribution,

Variance = [Σ(x - xbar)²/(N - 1)]

Standard deviation = σ = √[Σ(x - xbar)²/(N - 1)]

x = each variable

xbar = mean

N = number of variables

The mean is the average of the distribution. It is obtained mathematically as the sum of variables divided by the number of variables.

Mean = (Σx)/N

x = each variable

Σx = Sum of the variables

N = number of variables

Σx = 22 + 15 + 3 + 9 + 8 = 57

N = 5

Mean = xbar = (Σx)/N = (57/5) = 11.4

Variance = [Σ(x - xbar)²/(N - 1)]

Σ(x - xbar)² = (22 - 11.4)² + (15 - 11.4)² + (3 - 11.4)² + (9 - 11.4)² + (8 - 11.4)²

Σ(x - xbar)² = (10.6)² + (3.6)² + (-8.4)² + (-2.4)² + (-3.4)²

Σ(x - xbar)² = 112.36 + 12.96 + 705.6 + 5.76 + 11.56

Σ(x - xbar)² = 848.24

N - 1 = 5 - 1 = 4

Variance = [Σ(x - xbar)²/(N - 1)]

Variance = (848.24/4) = 212.06 = 212.1

Standard deviation = σ = √[Σ(x - xbar)²/(N - 1)]

Standard deviation = σ = √(212.06) = 14.6

Hope this Helps!!!

User Kevin Languasco
by
2.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.