Question

What is the density (in g/L) of a gas with a molar mass of 70.49g/mol at 0.874atm and 389K?

Answer 1

use the formula to solve for v. I forgot the formula which is why I cannot show it.

Answer 2

Step-by-step explanation:

According to the ideal gas law, PV = nRT

where, n = number of moles

Also, density =
`(mass)/(volume)`

Since, n =
`(mass)/(\molar mass)`

Therefore, ideal gas equation can also be written as follows.

PV = nRT

PV =
`\frac{mass}{\text{molar mass}} * RT`

`P * \text{molar mass}` = dRT

Hence, putting the given values into the above formula as follows.

`0.874 atm * 70.49 g/mol = d * 0.0821 Latm/mol K * 389 K`

6.161 atm g/mol =
`d * 31.94 Latm/mol`

d = 0.193 g/L

Thus, we can conclude that density of the given gas is 0.193 g/L.