Final answer:
To solve the given triangle with A = 46°, a = 31, and b = 27, we use the Law of Sines to first find angle B, then use the sum of angles to find angle C, and finally, use the Law of Sines again to find side c.
Step-by-step explanation:
To solve the triangle with the given information A = 46°, a = 31, and b = 27, we need to use the Law of Sines or the Law of Cosines. Since we have one angle and the side opposite to it (a = 31), as well as another side (b = 27), we first need to find angle B using the Law of Sines:
\frac{\sin(A)}{a} = \frac{\sin(B)}{b}
\frac{\sin(46°)}{31} = \frac{\sin(B)}{27}
By solving for sin(B), we get:
\sin(B) = \frac{\sin(46°) * 27}{31}
Next, we calculate the value of sin(B) and then angle B. After that, we can find angle C by using the fact that the sum of angles in a triangle is 180°:
A + B + C = 180°
C = 180° - A - B
Once we have angle C, we can use the Law of Sines again to find side c:
\frac{\sin(C)}{c} = \frac{\sin(A)}{a}
By rearranging and solving for c, we get:
c = \frac{\sin(C) * a}{\sin(A)}
This process will give us the lengths of all sides and the measurements of all angles, thus solving the triangle.