cmsee the figure below to better understand the problem
we have
AC=16 cm -------> OA=16/2=8 cm
BD=12 cm ------> OB=12/2=6 cm
Find out the value of x
Remember that
The area of the right triangle ABO is equal to
A=(1/2)(OB)(OA) ------> A=(1/2)(6)(8)=24 cm2
and the area of triangle ABO is equal to
A=(1/2)(AB)(x)
Find out the value of AB
Applying the Pythagorean Theorem
AB^2=OA^2+OB^2
AB^2=8^2+6^2
AB^2=100
AB=100
substitute
24=(1/2)(100)(x)
solve for x
24=50x
x=24/50
x=0.48 cm
The value of x is equal to the radius of the circle
so
the diameter is
D=2(0.48)
D=0.96 cm