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Students were asked to simplify the expression… The rubric and question is attached. Thank you so much!

Students were asked to simplify the expression… The rubric and question is attached-example-1
Students were asked to simplify the expression… The rubric and question is attached-example-1
Students were asked to simplify the expression… The rubric and question is attached-example-2
User Waam
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1 Answer

9 votes
9 votes

ANSWERS

Part A: student B's answer is incorrect. They made a mistake in step 3. See the explanation for the details about the mistakes

Part B: see the explanation

Step-by-step explanation

PART A

Let's simplify the expression first. This way we will see what should the final answer be and then we can compare it with the students' answers.

First, we can distribute the denominator into the subtraction,


(\csc\theta-\sin\theta)/(\csc\theta)=(\csc\theta)/(\csc\theta)-(\sin\theta)/(\csc\theta)=1-(\sin\theta)/(\csc\theta)

Then we have to replace the cosecant with its equivalent, since it is the reciprocal of the sine,


\csc\theta=(1)/(\sin\theta)

Replacing we have,


1-(\sin\theta)/(\csc\theta)=1-(\sin\theta)/((1)/(\sin\theta))=1-\sin^2\theta

From the following trigonometric identity,


\cos^2\theta+\sin^2\theta=1

We know that,


\cos^2\theta=1-\sin^2\theta

Hence, the simplified expression is cos²θ.

Therefore, we can conclude that student B simplified the expression incorrectly. Steps 1 and 2 are correct. Although they are not the same used here, those steps are correctly solved. Then, in step 3 the student replaced 1 - sin²θ as we did, but a mistake was made in the denominator because, instead of canceling out the sine, the student wrote sin²θ. This probably happened because the student replaced the cosecant by the sine of the angle instead of its reciprocal.

PART B

As stated in part A, student B made a mistake in step 3, where they replaced the cosecant with the sine,


Step\text{ }2:((1-\sin^2\theta)/(\sin\theta))/(\csc\theta)

For step 3, the following formula must be used,


\csc\theta=(1)/(\sin\theta)

So, step 3 is,


Step\text{ }3:((1-\sin^2\theta)/(\sin\theta))/((1)/(\sin\theta))

Then, in the next step, we simplify this division,


Step\text{ }4:((1-\sin^2\theta)\sin\theta)/(\sin\theta)=1-\sin^2\theta

And then, we simplify using the trigonometric identity named in part A,


Step\text{ }5:\cos^2\theta

User Lior Pollak
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