Answer:
3
Step-by-step explanation:
Hello,
In this case, as nitrogen is not bearing any formal charge, we apply its mathematical definition to find such oxidation state:
Formal charge= # of valence electrons - # of lone-pair electrons - 1/2 # of bond pair electrons
Since no formal charge is born, no lone-pair electrons are formed and 6 bond pair electrons are always present for the nitrogen to complete the octate, the valence turns out into:
# of valence electrons = 0 + 0 + 1/2 * 6
# of valence electrons = 3
Best regards.