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Please help solve this:
3^(x + 1) = 100

1 Answer

3 votes
remember, you can do anything to an equaiton as long as you do it to both sides

also

log(a^x)=xlog(a)
and
ln(x)=log_e(x)
ok
if no base is stated, assume log=
log_(10)
I'm going to use ln instead of log because ln is easier to find on a calculator


3^(x+1)=100
take ln of both sides

ln(3^(x+1))=ln(100)

(x+1)ln(3)=ln(100)

xln(3)+1ln(3)=ln(100)
minus ln(3) both sides

xln(3)=ln(100)-ln(3)
divide both sides by ln(3)

x=(ln(100))/(ln(3))-1

or if you wanted to use log base 10

3^(x+1)=100
take log both sides

log(3^(x+1))=log(100)

log(3^(x+1))=2

(x+1)log(3)=2

xlog(3)+log(3)=2
minus log(3) both sides

xlog(3)=2-log(3)
divide both sides by log(3)

x=(2)/(log(3))-1



so

x=(ln(100))/(ln(3))-1
or if you wanted log

x=(2)/(log(3))-1
User Qqtf
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