Question

Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide that Jenny gets to choose their lunch order if te flower she randomly picks from the bouquet is a carnation or a rose. What is the probability that Jenny gets to choose lunch?

Answer 1

The probability that Jenny gets to choose lunch is 64% 0.64 (rounded) or 0.636.

Work:

Number of roses and carnations divided by the total number of flowers

7/11 = 0.636 = 0.64 (rounded)

once again same answer