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An earthquake registered 7.4 on the Richter scale. If the reference intensity of this quake was 2.0 × 1011, what was its intensity?

User Yas
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1 Answer

5 votes

Answer:

The intensity was
5.02377* 10^(18)

Explanation:

We are given

An earthquake registered 7.4 on the Richter scale

so, RC=7.4

the reference intensity of this quake was 2.0 × 10^11

so,


I_r=2.0* 10^(11)

now, we can use formula


RS=log((I)/(I_r) )

now, we can plug values


7.4=log((I)/(2.0* 10^(11)) )

now, we can solve for I


10^(7.4)=(I)/(2.0* 10^(11))


I=10^(7.4)* 2.0* 10^(11)


I=5.02377* 10^(18)


User Natemcmaster
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