Question

A circle has its center at (-2, 5) and a radius of 4 units. What is the equation of the circle? (1 point)

(x + 2)2 + (y - 5)2 = 16
(x + 2)2 + (y + 5)2 = 16
(x + 2)2 + (y - 5)2 = 4
(x - 2)2 + (y + 5)2 = 4

Answer 1

`\bf \textit{equation of a circle}\\\\ (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 \qquad \begin{array}{lllll} center\ (&{{ h}},&{{ k}})\qquad radius=&{{ r}}\\ &-2&5&4 \end{array}`

Answer 2

equation of circle (x +2)² + (x + 5)² = 16.

Explanation:

Given : A circle has its center at (-2, 5) and a radius of 4 units.

To find : What is the equation of the circle.

Solution : We have given center at (-2, 5) and radius = 4 units .

Standard form of circle : (x -h)² + (x + k)² = r²

Where, ( h, k) is center , r = radius .

Plugging the values of h , k and r in standard equation

(x -(-2))² + (x + 5)² = (4)²

(x +2)² + (x + 5)² = 16.

Therefore, equation of circle (x +2)² + (x + 5)² = 16.