Question

Can someone help me with this question

Answer 1

`x^(2) +2x-5=0 \\ D=b^2-4ac=2^2-4*1*(-5)=4+20=24 \\ x_(1,2)= (-bб √(D) )/(2a)= (-2б √(24) )/(2)=(-2б 2√(6) )/(2)= (-2)/(2)б (2 √(6) )/(2) =-1б √(6)`

Answer:
B. x = -1 - √6
C. x = -1 + √6