Question

How many carbon atoms are there in a diamond (pure carbon) with a mass of 52 mg?

Answer 1

Note:
A unit cell of diamond has 8 carbon atoms and has a volume of 10⁻²¹ cm³.
Carbon diamond has a density of about 3.52 g/cm³

Therefore the number of atoms in a carbon diamond with a mass of 52 mg is

`( (8 \, atoms)/(10^(-21) \, cm^(3)) )*( (1 \, cm^(3))/(3.52 \, g) )*(52 * 10^(-3) \, g) = 1.182 * 10^(20) \, atoms`

Answer: 1.182 x 10²⁰ atoms