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If ray BD bisects angle CBE, ray BC is transparent to ray BA, angle CBD = (3x + 25) degrees, and angle DBE = (7x - 19) degrees, find angle ABD

If ray BD bisects angle CBE, ray BC is transparent to ray BA, angle CBD = (3x + 25) degrees-example-1
User Suzann
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2 Answers

6 votes
check the picture below.
If ray BD bisects angle CBE, ray BC is transparent to ray BA, angle CBD = (3x + 25) degrees-example-1
User Perennialista
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6.4k points
3 votes

Answer: The required measure of angle ABD is 148°.

Step-by-step explanation: Given that ray BD bisects angle CBE, ray BC is transparent to ray BA.

Also,


m\angle CBD=(3x+25)^\circ,~~m\angle DBE=(7x-19)^\circ,~~m\angle ABC=90^\circ.

We are to find the measure of angle ABD.

Since ray BD bisects angle CBE, so we have


m\angle CBD=m\angle DBE\\\\\Rightarrow (3x+25)^\circ=(7x-19)^\circ\\\\\Rightarrow 3x+25=7x-19\\\\\Rightarrow 7x-3x=25+19\\\\\Rightarrow 4x=44\\\\\Rightarrow x=(44)/(4)\\\\\Rightarrow x=11.

So, we get


m\angle CBD=(3*11+25)^\circ=58^\circ.

Therefore,


m\angle ABD=m\angle ABC+m\angle CBD=90^\circ+58^\circ=148^\circ.

Thus, the required measure of angle ABD is 148°.

User Slowik
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6.1k points
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