189,942 views
13 votes
13 votes
Hello i need some help with my ap physics assignment for school

Hello i need some help with my ap physics assignment for school-example-1
User Anton Chikin
by
3.1k points

1 Answer

15 votes
15 votes

x is the distance straight east

a) The right triangle representing the scenario is shown below

G is the starting point

F is the final point

x is the distance straight east

y is the distance straight North

The required angle = 90 - 30 = 60

Taking 30 degrees as the reference angle,

hypotenuse = 5

adjacent side = x

opposite side = y

To find x, we would apply the cosine trigonometric ratio which is expressed as

cosθ = adjacent side/hypotenuse

Cos 60 = x/5

By cross multiplying,

x = 5cos60 = 2.5

To find y, we would apply the sine trigonometric ratio which is expressed as

cosθ = opposite side/hypotenuse

Sin 60 = y/5

By cross multiplying,

y = 5Sin60 = 4.33

Thus, the distances are

2.5 km east

4.33 km North

b) If the east and north legs are reversed, the route would be GBF

GB(north) = 5cos30 = 4.33 km

BF(east) = 5sin30 = 2.5 km

The distances are the same. Thus, you will still arrive at the same point

Hello i need some help with my ap physics assignment for school-example-1
User Davmac
by
3.1k points