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Can someone help me on problem 79

Can someone help me on problem 79-example-1
User Lexual
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1 Answer

5 votes

79

a) the multiplier would be 1 - 0.15 = 0.85

b) value = 27,000*0.85^y ( with y being the number of years)

c) y = 5 years

27000 x 0.85^5 = 11980.04

the car will be valued at $11,980.04 after 5 years

User Jasiry
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