Question

What is the approximate value of q in the equation below.

q+logbase2 6=2q+2

-1.613
-1.522
0.585
3.079


I have chosen -1.613 but it was wrong apparently.

Answer 1

The answer is 0.585.
q+logbase2 6=2q+2
The binary logarithm of 6 is 2.585 .
2q - q = 2.585 - 2
q = 0.585

Answer 2

The correct option is: 0.585

Step-by-step explanation

Given equation is:
`q+log_(2)6 = 2q+2`

First we will subtract
`q` from both sides and also subtract 2 from both sides. So, we will get.........

`q+log_(2)6-q-2=2q+2-q-2\\ \\ log_(2)6 -2= q`

Now, the value of
`log_(2)6 = 2.58496.....`

So,
`q= 2.58496.... -2 = 0.58496.... \approx 0.585`

Thus, the approximate value of
`q` will be 0.585