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Evaluate ƒ(x) = –x2 + 1 for x = –3.
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1 vote
Evaluate ƒ(x) = –x2 + 1 for x = –3.

User James Stewart
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2 Answers

3 votes
f(x)= 7
you take -x and replace it with -3 witch turns it to a positive then multiply 2 times 3 then add one There for x is 7
User NIKUNJ KHOKHAR
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6 votes
ƒ(x) = -(-3)^2 + 1
ƒ(x) = - 9 + 1
ƒ(x) = - 8
User CoolestNerdIII
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9.1k points
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