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Including Jose, there are 8 people in his family. If order matters, how many ways can he arrange his family members into a row if Jose must sit in the first seat?

User Yeahumok
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2 Answers

0 votes

Final answer:

There are 5040 ways Jose can arrange his family members in a row if order matters and he must sit in the first seat.

Step-by-step explanation:

To find the number of ways Jose can arrange his family members in a row, we need to consider the number of ways the remaining 7 people can be arranged.

Since the order matters and Jose must sit in the first seat, we can think of it as arranging 7 people starting from the second seat.

There are 7 choices for the second seat, then 6 choices for the third seat, and so on, until the last person has 1 choice for the eighth seat.

Therefore, the total number of ways Jose can arrange his family members in a row is 7! (7 factorial), which is equal to -

= 7 × 6 × 5 × 4 × 3 × 2 × 1

= 5040 ways.

User Russell England
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8.0k points
4 votes

Answer:

840 on edge

Step-by-step explanation:

User Trey Balut
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8.7k points