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In one baseball season, Peter hit twice the difference of the number of home runs Alice hit and 6. Altogether, they hit 18 home runs. How many home runs did each player hit that…
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In one baseball season, Peter hit twice the difference of the number of home runs Alice hit and 6. Altogether, they hit 18 home runs. How many home runs did each player hit that…
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Oct 13, 2018
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In one baseball season, Peter hit twice the difference of the number of home runs Alice hit and 6. Altogether, they hit 18 home runs. How many home runs did each player hit that season? Let h represent Alice's home runs.
Mathematics
middle-school
OllieB
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h = Alice's home runs
p = Peter's home runs
p = 2(h - 6)
p + h = 18
Simplified:
p = 2h - 12
p - 2h = -12
p + h = 18
Solve simultaneously:
p - 2h = -12 ...
1
p + h = 18 ...
2
1 - 2:
-3h = - 30
h = -30/-3
h = 10
Substitute into 2:
p + h = 18
p + 10 = 18
p = 18 - 10
p = 8
Therefore, Peter hit 8 home runs and Alice hit 10 homeruns.
Alexander Kirov
answered
Oct 20, 2018
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Alexander Kirov
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