Question

How much water should be mixed with 237 ml of​ ammonia, whose strength is​ 100%, in order to create a mixture that is diluted to a​ 75% strength?

Answer 1

In this case, you know your solution volume( 237ml) and your solution strength (100%). You want to make a mixture that has 75% strength, which means it has 75% of ammonia and 25% is the diluting water. Then the calculation would be:

Water= 25%/75% x 237ml = 79ml of water.

Answer 2

79 ml

Step-by-step explanation

You have 237 237 ml of​ ammonia, whose strength is​ 100%.

If you want to make it 75%, then;

let 75% ⇒ 237 ml of ammonia and

25% ⇒ x ml of water.

∴ x = (25% ×237) / 75%

= 5,925/75

= 79 ml of water.