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a local basketball court dimensions are 50 ft long, 20 ft wide, the court is lost square footage by 1/4. what are the new dimensions of the court. write the equation out then solve.
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a local basketball court dimensions are 50 ft long, 20 ft wide, the court is lost square footage by 1/4. what are the new dimensions of the court. write the equation out then solve.

User PKonstant
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1 Answer

6 votes
50x20=1000

1000x(1/4)=250

1000-250=750ft^2
User Paul McMahon
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