Question

What is the mass in grams of carbon dioxide that would be required toreact with 80.5 g of LiOH in the following chemical reaction?2 LiOH(s) + CO2(g) → Li CO3(s) + H,O(1)

Answer 1

• Given the balanced equation :

2LiOH + CO2 → Li2CO3 + H2O

• We can see that 2 moles of LiOH reacts with 1 mole of CO2.

1. Lets calculate number of moles

n = massLiOH/Molecular massLiOH

→Where molecular mass LiOH = 23.95 g/mol, and given Mass of LiOH = 80.5g

∴ n = 80.5g/23.95g/mol

n = 3.36 mol

2. Determine moles of CO2 required from the equation ratio:

2 moles LiOH : 1 Mol CO2 → 1 mol Li2O3 + 1 mol H20

So,

• Moles of CO2 required = 3.36 mol/2 = 1.68 moles

,

• Molar Mass CO2 = 44.01 g/mol

,

• Mass of CO2 = 44.01 g /moles* 1.68 moles

= 73.94 g

• This means that 73.94g of CO2 would be required to react with 80.5gLiOH