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Find the center of the circle that can be circumscribed about EFG with E(2,2),F(2,-2), and G(6,-2)

User Carpela
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hmmm I'd say the center of the circle will end up at the center of the triangle, namely the Centroid of the triangle circumscribed in the circle.


\bf \textit{Centroid of a Triangle} \begin{array}{llll} \stackrel{E(2,2)~~F(2,-2)~~G(6,-2)}{\left(\cfrac{2+2+6}{3}\quad ,\cfrac{2-2-2}{3}\quad \right)} \end{array}
User Nilesh Ukey
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