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Use​ Gauss's approach to find the following sums​ (do not use​ formulas). 1+3+5+7+...999

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S=1+3+5+\cdots+995+997+999

S=999+997+995+\cdots+5+3+1

\implies 2S=(1+999)+(3+997)+(5+995)+\cdots+(995+5)+(997+3)+(999+1)


2S=\underbrace{1000+1000+\cdots+1000+1000}_{500\text{ times}}

(We are adding 500 instances of 1000 because that's how many odd numbers there are between 1 and 1000, inclusive.)


2S=500*1000=500000

\implies S=250000
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