Question

What is the midpoint coordinates of segment HX H(13,8) X(-6,-6)

Answer 1

midpoint of (x1,y1) and (x2,y2) is


`((x_1+x_2)/(2),(y_1+y_2)/(2))`

so the midpoint of HX is the mdpoint of (13,8) and (-6,-6)
which is


`((13-6)/(2),(8-6)/(2)=`

`((7)/(2),(2)/(2)=`

`(3.5,1)`

the midpoint is (3.5,1)