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What is the midpoint coordinates of segment HX H(13,8) X(-6,-6)

User Amit Gupta
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1 Answer

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midpoint of (x1,y1) and (x2,y2) is


((x_1+x_2)/(2),(y_1+y_2)/(2))

so the midpoint of HX is the mdpoint of (13,8) and (-6,-6)
which is


((13-6)/(2),(8-6)/(2)=

((7)/(2),(2)/(2)=

(3.5,1)

the midpoint is (3.5,1)
User Keran
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