Question

The first aircraft has 75 more seats than the second aircraft. The third aircraft has 49 fewer seats than the second aircraft. If their total number of seats is 401​, find the number of seats for each aircraft.

Answer 1

1st = 75+x

2nd = x

3rd = x-49

401 = 75 +x+ x+ +x-49

401 = 75+3x-49

401 = 3x+26

375=3x

x=375/3 = 125

1st = 125+75 = 200

2nd = 125

3rd = 125-49 = 76

200 + 125 +76 = 401