107k views
0 votes
Suppose $100 dollars is deposited into an account and the account doubles every 8 years . How much will in the account after 40years ?

2 Answers

2 votes
year 0 : D = $100
year 8 : D= $200
year 16 : D = $400
year 24 : D = $800
year 32 : D= $1600
year 40 : D= $3200

That's the longest way to do it :

40/8 = 5 ; the account is gonna doubles 5 times


D(year40) = 100*2^(5) = 100*32 = 32000

User Natasa
by
7.2k points
6 votes
yay, doubling time


the equation is

A=P(2)^(t)/(d)

A=final amount
P=initial amount
t=time elapsed in years
d=doubling time in years

ok

A=A
P=100
d=8yrs
t=40yrs

so


A=100(2)^(40)/(8)

A=100(2)^5

A=100(32)

A=3200


there will be $3200 in the account after 40 years
User Annelyn
by
8.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories