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Solve the following system of equations by substitution. 3x + 2y = -12 x = 2 A. (2, -9) B. (-2, -3) C. (3, 2) D. (2, 3)
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Solve the following system of equations by substitution. 3x + 2y = -12 x = 2 A. (2, -9) B. (-2, -3) C. (3, 2) D. (2, 3)

User Sayayin
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Plugging it in, we get (3)(2)+2y=-12 and 6+2y=-12. Subtracting 6 from both sides, we get -18=2y and dividing by 2 we get y=-9  to get (2, -9) since x is first in the pair
User DoubleBass
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