Question

Circle O and circle P are congruent. Given that AB = DE , what can you conclude from the diagram?

Answer 1

Since the radius is the same, that means that OBA=PDE

Answer 2

Answer: We can conclude that,
`\triangle OAB\cong \triangle PD E`.

Step-by-step explanation: Since, If two circles are congruent then their radius is equal.

Therefore, we can say, OA=OB=PD=PE.

Since, in triangles OAB and PDE,

OA=PD,

OB=PE,

And, AB=DE ( given)

Therefore, by SSS postulate we can say,
`\triangle OAB\cong \triangle PD E` .

Note: we can also say by the diagram,
`\angle AOB` and
`\angle PD E` are congruent.