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The function f(t)=5tan2t does not have an amplitude and has a period of \pi

yes or no?

2 Answers

5 votes
It's multiplied by 5, so the amplitude is 5.

The period is pi/2 since it's tan(2t)
User Adinah
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4 votes

Answer:

no

Explanation:

The function is a tangent, therefore, there is no amplitude. The range is all reals, but the domain is where it gets funky.

there is an asymptote at pi/4, and the period is located at every multiple of pi/2. Because pi/2 is not equivilant to pi, this portion of the question is false.

This is a conditional question, so both have to be true. Therefore, the answer is no.

User Herku
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