956 views
4 votes
Given the function f(x) = The quantity of 2x minus 5, divided by 3, which of the below expressions is correct?

f−1(x) = The quantity of 5 minus 2x, divided by 3.
f−1(x) = The quantity of 3x minus 5, divided by 2.
f−1(x) = The quantity of 3x plus 5, divided by 2.
f−1(x) = The quantity of negative 2x minus 5, divided by 3.

User Vita
by
8.7k points

1 Answer

2 votes
hello :
f(x) = (2x-5)/3
f−1(x) = (3x+5)/2
because : f(x) 0 f−1(x) = x and f−1(x) 0 f(x) = x
f(x) 0 f−1(x) = f( f−1(x) ) = f ((3x+5)/2) = (2(3x+5)/2 - 5))/3 = 3x /3 =x
same cacul for : f−1(x) 0 f(x) = x
User Siva Praveen
by
8.1k points

Related questions

asked Sep 10, 2024 2.2k views
Jason Pan asked Sep 10, 2024
by Jason Pan
8.5k points
1 answer
1 vote
2.2k views
asked Jun 15, 2024 71.8k views
Savad asked Jun 15, 2024
by Savad
9.0k points
1 answer
2 votes
71.8k views