Question

Help please and thank you

Answer 1

remember

`(a^b)^c=a^(bc)`
and

`(x^a)/(x^b)=x^(a-b)`


so


`((7^2)^5)/(7^(-6))=`

`(7^(2*5))/(7^(-6))=`

`(7^(10))/(7^(-6))=`

`7^(10-(-6))=`

`7^(10+6)=`

`7^(16)`

the answer is D