Question

Graph the line with slope -1 passing through the point (-2, -2).

Answer 1

`\bf slope = {{ m}}= \cfrac{rise}{run} \implies -1\implies \cfrac{-1}{1} \\\\\\ \textit{that means, from point} ~\boxed{(-2,-2)}\\\\ \textit{you go -1 over the y-axis and 1 over the x-axis} \\\\\\ (\stackrel{run}{-2}~,~\stackrel{rise}{-2})\\\\\\ (\stackrel{1}{-2}~,~\stackrel{-1}{-2})\implies (-2+1~,~-2-1)\implies \boxed{(-1,-3)}`

so.... there, using the slope's rise/run values, you can get the subsequent point, and to graph a LINEar equation, since it's just a LINE, all you need is two points, graph those two, run a line through them, that's the graph of the line.