153k views
1 vote
Solve these systems for (x,y,z)
-x+y+z=4
-x+2y-3z=-6
2x-4y+8z=18

1 Answer

7 votes
Multiply the first equation by -1 and add it to the second one, getting
y-4z=-10

Multiply the first equation by 2 and add it to the third one, getting -2y+10z=26

As you can see, we eliminated x and turned it into two equations with 2 variables.

Multiply the first new equation by 2 and add it to the second one to get
2z=6 and z=3. Substitute it in to -2y+10z=26 to get y=2 and substitute it into -x+y+z=4 to get x=1
User Aditya Garg
by
7.7k points

Related questions

asked Feb 15, 2024 66.2k views
Ian Jennings asked Feb 15, 2024
by Ian Jennings
7.3k points
2 answers
5 votes
66.2k views
asked Dec 17, 2024 137k views
Tom Yates asked Dec 17, 2024
by Tom Yates
7.6k points
1 answer
4 votes
137k views
asked Mar 17, 2024 44.6k views
Bill Lynch asked Mar 17, 2024
by Bill Lynch
8.3k points
1 answer
2 votes
44.6k views