Question

The average acceleration of the shuttle during its 7.5 minute run is 18m/s what velocity does it theoretically achieve at the end of that time?

Answer 1

To calculate the final velocity of the shuttle, the kinematic equation v = u + at is used with an acceleration of 18 m/s² over 450 seconds, resulting in a final velocity of 8100 m/s.

Step-by-step explanation:

The question involves calculating the final velocity of a shuttle based on its average acceleration over a given time period. To find this, we can use the kinematic equation v = u + at, where v is the final velocity, u is the initial velocity (which we can assume to be 0, since the question does not specify otherwise), a is the acceleration, and t is the time. Converting the given time from minutes to seconds (7.5 minutes = 450 seconds) and using the provided acceleration of 18 m/s², we get: v = 0 + (18 m/s²)(450 s) = 8100 m/s Therefore, the shuttle theoretically achieves a velocity of 8100 m/s at the end of the 7.5 minute run.

Answer 2

Convert 7.5min to s. Hence, 7.5min = 450s
I am assuming the initial velocity is zero here and that 18 is the acceleration and not the velocity.
Therefore you use this formula:
acceleration= (vfinal)/t [Note: velocity initial is not included as it is zero, so it would just cancel out]
vfinal= a*t
=18m/s²*450s
= 8100m/s or 8.1*10³m/s if you correct to proper sigdigs.
Hope this helps!