Question

The elevator of a large building is to raise a net mass of 400 kg at a constant speed of 12 m/s using an electric motor. minimum power rating of the motor should be

Answer 1

P =Force*velocity
=mass*acceleration due to gravity*velocity
=(400kg)(9.81m/s²)(12m/s)
=47088W or 4.7*10⁴W

Answer 2

`P=47.040 \ kW`

Step-by-step explanation:

In the question given things are:

Total mass of elevator,
`m=400\ kg`.

It is also given that it moves with constant speed,
`v=12\ m/s`.

So, power for object moving in constant velocity is given as.

`P=m * g * v`.

Putting all values in above equation.

`P=400* 9.8 * 12=47040 \ W=47.040 \ kW`.

Hence, it is the required solution.