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Given that g(x)=3x²-5x+7 find the following:
g(-x)

User EkriirkE
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1 Answer

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g(x) = 3x² - 5x + 7
g(-x) = -(3x² - 5x + 7)
g(-x) = -3x² + 5x - 7

This equation cannot be solved because of a few reasons,

1. This equation didn't show that it equals to 0.
2. Even if it equals to zero, square root of a negative number cannot be solved.
(I will show you what I mean)

-3x² + 5x - 7
is the same as
3x² - 5x + 7
by shifting the equation,

for example,
1 - 3 = -2
shifting other side
2 = -1 + 3

using 3x² - 5x + 7 to solve,


Solve\ using\ the\ formular\ \ \boxed{ x= { (-b \pm √(b^2-4ac) )/(2a) } }
a = 3
b = -5
c = 7

x= { \frac {-(-5) \pm √( (-5)^2-4(3)(7) ) }{2(3)} }

x= { \frac {5 \pm √(-59) }{6} }

∴This equation cannot be solved.
User Jankapunkt
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