Answer:
NaF
Step-by-step explanation:
If the 54.76% of the sample is sodium and 45.24% is fluorine. Mass of each atom is:
Na: 4.2g × 0.5476 = 2.3g
F: 4.2g × 0.4524 = 1.9g
In moles:
Na: 2.3g × (1mol / 22.99g) = 0.1 moles
F: 1.9g × (1mol / 19) = 0.1 moles
As empirical formula is defined as the simplest whole-number ratio of atoms in a compound, the ratio of Na:F is:
0.1 / 0.1 = 1. Thus, empirical formula is:
NaF