Question

Write the formulas of the compounds formed by Pb4+ with the following anions: CN−, ClO3−, SO32−, HPO42−

Answer 1

Pb(CN)₄
Pb(ClO₃)₄
Pb(SO₃)₂
Pb(HPO₄)₂

:•)

Answer 2

a)
`Pb(CN)_(4)`

b)
`Pb(ClO_(3))_(4)`

c)
`Pb(SO_(3))_(2)`

d)
`Pb(HPO_(4))_(2)`

Step-by-step explanation:

In the given scenario, Pb⁴⁺ is a cation which combines with various anions in order to form a neutral ionic compound. This implies that the charges on the cation and anion must be balanced so that the net charge on the molecule is zero.

a) Pb⁴⁺ with CN⁻

Charge on Pb = +4

Charge on CN = -1

To form a neutral molecule, each Pb⁴⁺ should combine with 4 CN⁻

Formula:
`Pb(CN)_(4)`

b) Pb⁴⁺ with ClO₃⁻

Charge on Pb = +4

Charge on ClO₃⁻ = -1

To form a neutral molecule, each Pb⁴⁺ should combine with 4 ClO₃⁻

Formula:
`Pb(ClO_(3))_(4)`

c) Pb⁴⁺ with SO₃²⁻

Charge on Pb = +4

Charge on SO₃²⁻ = -2

To form a neutral molecule, each Pb⁴⁺ should combine with 4 ClO₃⁻

Formula:
`Pb(SO_(3))_(2)`

d) Pb⁴⁺ with HPO₄²⁻

Charge on Pb = +4

Charge on HPO₄²⁻ = -2

To form a neutral molecule, each Pb⁴⁺ should combine with 4 ClO₃⁻

Formula:
`Pb(HPO_(4))_(2)`