Question

Find cot θ if csc θ = negative square root of thirty seven divided by six and tan θ > 0.

Answer 1

Answer: 1/6

Explanation:

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Answer 2

You can use the trigonometric identity
`1+\cot^2{x}=\csc^2{x}`.


`1+\cot^2{\theta}=((-√(37))/(6) )^2 \\ 1+\cot^2{\theta}=(37)/(36) \\ \cot^2{\theta}=(1)/(36) \\ \cot{\theta}=(1)/(6)`

The requirement that
`tan(\theta)\ \textgreater \ 0` eliminates -1/6 from being another solution.