Question

F(x)=x^3-9x g(x)=x^2-2x-3
What is f(x)/g(x), if x>3

Answer 1

Your answer is 9f/g. Hope it helps

Answer 2

F(x)=x^3-9x
and
g(x)=x^2-2x-3

so you just need to divide f(x) by g(x)

Therefore:

f(x)/g(x) = (x^3-9x) / (x^2-2x-3)

and of course you need to factor these two function to see if some factor would cancel another

x^3-9x = x(x^2-9)=x(x-3)(x+3)
and
x^2-2x-3 = (x-3)(x+1)


SO:

`f(x)/g(x) = ((x^3-9x))/((x^2-2x-3)) = (x(x-3)(x+3) )/((x-3)(x+1)) = (x(x+3))/(x+1)`


Done
:)


I hope you got the idea!